AP CSP Day 19: Https Encryption
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Practice Question
In a network, four devices (A, B, C, D) are connected: A to B, A to C, B to D, and C to D. If the connection between A and B fails, can device A still communicate with device D?
The network has redundant paths. Although the A-B connection fails, A can still reach D through the alternative path A → C → D. This is fault tolerance through redundancy — multiple paths ensure communication continues despite individual failures.
A) The existence of an alternative path (A-C-B) means communication is still possible. B is correct. C) No repair is needed because the alternate path through C works immediately. B) Device D remains connected to C and B; it is not isolated.
Students only consider the most direct path and forget to check for alternative routes. In fault tolerance questions, always trace ALL possible paths.
For network fault tolerance questions, draw the diagram and systematically trace every possible path between the two endpoints. If at least one path exists, communication is possible.
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