AP CSA Unit 1 Day 23: Pass By Value For Primitives

Unit 1, Section 1.8 • Cycle 2
Day 23 Advanced Practice • Harder Difficulty
Focus: Ignored return Hard Predict Output

Advanced Practice Question

Consider the following code:
public static void change(int x) {
    x = 10;
}

public static void main(String[] args) {
    int num = 5;
    change(num);
    System.out.println(num);
}
What is printed?
Difficulty: Hard | Topic: Pass-by-value for primitives | Cycle: 2 (Advanced)
Why This Answer?

This question tests your understanding of ignored return. The correct answer demonstrates precise knowledge of how Java handles pass-by-value for primitives.

Common Mistakes
Mistake #1: Misunderstanding the concept

Students often make errors with pass-by-value for primitives by not carefully tracing execution or understanding the underlying concept.

Mistake #2: Not considering edge cases

This Cycle 2 HARD question requires careful attention to detail and understanding of how Java behaves in this scenario.

AP Exam Strategy

For questions testing pass-by-value for primitives, always trace execution step-by-step. Write down intermediate values. Don't skip steps - the AP exam rewards precise understanding of Java behavior.

Master This Topic

This Cycle 2 HARD question tests pass-by-value for primitives. Review Unit 1 concepts to build mastery of primitive types, objects, and String manipulation.

  • Understanding ignored return
  • Tracing code execution accurately
  • Avoiding common pitfalls
View Unit 1 Study Guide

Ready for More Challenges?

Cycle 2 questions prepare you for the hardest AP CSA exam questions.

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