AP CSA Unit 2 Day 15: Boolean Algebra Equivalence
Share
Unit 2, Selection & Iteration • Cycle 2
Day 15 Advanced Practice • Harder Difficulty
Focus: De Morgan's Law
Hard
Boolean Algebra (Equivalence)
Advanced Practice Question
Format: Boolean Algebra (Equivalence)
Which expression is logically equivalent to `!(p && q)`?
Which expression is logically equivalent to `!(p && q)`?
Difficulty: Hard |
Topic: Boolean Algebra (Equivalence) |
Cycle: 2 (Advanced)
Why This Answer?
De Morgan's Law: `!(P && Q)` becomes `!P || !Q`.
Common Mistake
Watch Out!
Using the wrong operator after negation (`&&` instead of `||`).
AP Exam Strategy
Negating an AND flips it to OR.
Master This Topic
This Cycle 2 HARD question tests de morgan's law. Review Unit 2 concepts to build mastery of selection and iteration.
- Understanding de morgan's law
- Tracing code execution accurately
- Avoiding common pitfalls
Ready for More Challenges?
Cycle 2 questions prepare you for the hardest AP CSA exam questions.
Study Games Practice FRQs