AP CSA Unit 2 Day 21: Iteration Break

February 6, 2026

Unit 2, Selection & Iteration • Cycle 2

Day 21 Advanced Practice • Harder Difficulty

Focus: Early Exit Hard Iteration (break)

Advanced Practice Question

Format: Iteration (break)

What is printed?

for (int i = 0; i < 10; i++) {
    if (i == 5) {
        break;
    }
    System.out.print(i + " ");
}

Difficulty: Hard | Topic: Iteration (break) | Cycle: 2 (Advanced)

Why This Answer?

The loop adds 1 and 2, then breaks when i is 3. Sum is 3.

Common Mistake

Watch Out!

Including 3 even though the break occurs before the addition.

AP Exam Strategy

When break triggers, the loop stops immediately—no further statements run in that iteration.

This Cycle 2 HARD question tests early exit. Review Unit 2 concepts to build mastery of selection and iteration.

Cycle 2 questions prepare you for the hardest AP CSA exam questions.