AP CSA Unit 2 Day 3: Short Circuit Logic

Unit 2, Selection & Iteration • Cycle 2
Day 3 Advanced Practice • Harder Difficulty
Focus: Short-Circuit Evaluation Hard Short-Circuit Logic

Advanced Practice Question

Format: Short-Circuit Logic

What is printed?
int x = 5;
if (x > 0 && x / 0 == 0) {
    System.out.println("True");
}
System.out.println("Done");
Difficulty: Hard | Topic: Short-Circuit Logic | Cycle: 2 (Advanced)
Why This Answer?

Because `x != 0` is false, Java short-circuits `&&` and does NOT evaluate `10 / x`. So `ok` becomes false and prints `false`.

Common Mistake
Watch Out!

Assuming both sides of `&&` always run, leading to a mistaken divide-by-zero.

AP Exam Strategy

With `&&`, if the left side is false, the right side is skipped.

Master This Topic

This Cycle 2 HARD question tests short-circuit evaluation. Review Unit 2 concepts to build mastery of selection and iteration.

  • Understanding short-circuit evaluation
  • Tracing code execution accurately
  • Avoiding common pitfalls
View Unit 2 Study Guide

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