AP CSA Unit 4 Day 17: Array Reverse

Unit 4, Data Collections • Cycle 2
Day 17 Advanced Practice • Harder Difficulty
Focus: Array Reverse Hard Array Reverse

Advanced Practice Question

Format: Array Reverse

What is the output?
int[] arr = {1, 2, 3, 4, 5};

for (int i = 0; i < arr.length / 2; i++) {
    int temp = arr[i];
    arr[i] = arr[arr.length - 1 - i];
    arr[arr.length - 1 - i] = temp;
}

System.out.println(Arrays.toString(arr));
Difficulty: Hard  |  Topic: Array Reverse  |  Cycle: 2 (Advanced)
Why This Answer?

Standard array reversal: swap first with last, second with second-to-last, etc. Only goes to length/2 to avoid double-swapping. Result: [5, 4, 3, 2, 1].

Common Mistake
Watch Out!

Looping to arr.length instead of arr.length/2, causing double-swap.

AP Exam Strategy

Reverse: loop to length/2, swap arr[i] with arr[length-1-i].

Master This Topic

This Cycle 2 HARD question tests array reverse. Review Unit 4 concepts to build mastery of data collections.

  • Understanding array reverse
  • Tracing code execution accurately
  • Avoiding common pitfalls
View Unit 4 Study Guide

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