Unit 2 Cycle 2 Day 26: Iteration (break in nested loops)
Share
Unit 2, Selection & Iteration • Cycle 2
Day 26 Advanced Practice • Harder Difficulty
Focus: Break Scope
Hard
Iteration (break in nested loops)
Advanced Practice Question
Format: Iteration (break in nested loops)
What is printed?
What is printed?
"apcs-keyword">int c = "apcs-number">0;
"apcs-keyword">for ("apcs-keyword">int i = "apcs-number">1; i <= "apcs-number">3; i++)
{
"apcs-keyword">for ("apcs-keyword">int j = "apcs-number">1; j <= "apcs-number">3; j++)
{
"apcs-keyword">if (j == "apcs-number">2)
{
break;
}
c++;
}
}
System.out.println(c);
Difficulty: Hard |
Topic: Iteration (break in nested loops) |
Cycle: 2 (Advanced)
Why This Answer?
For each i, the inner loop increments c when j=1, then breaks at j=2. That's 1 increment per outer iteration. Outer runs 3 times → c = 3.
Common Mistake
Watch Out!
Thinking `break` exits both loops (it exits only the inner loop).
AP Exam Strategy
`break` only exits the loop it is directly inside.
Master This Topic
This Cycle 2 HARD question tests break scope. Review Unit 2 concepts to build mastery of selection and iteration.
- Understanding break scope
- Tracing code execution accurately
- Avoiding common pitfalls
Ready for More Challenges?
Cycle 2 questions prepare you for the hardest AP CSA exam questions.
Study Games Practice FRQs