Unit 2 Cycle 2 Day 3: Short-Circuit Logic
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Unit 2, Selection & Iteration • Cycle 2
Day 3 Advanced Practice • Harder Difficulty
Focus: Short-Circuit Evaluation
Hard
Short-Circuit Logic
Advanced Practice Question
Format: Short-Circuit Logic
What is printed?
What is printed?
"apcs-keyword">int x = "apcs-number">0;
"apcs-keyword">boolean ok = (x != "apcs-number">0) && ("apcs-number">10 / x > "apcs-number">1);
System.out.println(ok);
Difficulty: Hard |
Topic: Short-Circuit Logic |
Cycle: 2 (Advanced)
Why This Answer?
Because `x != 0` is false, Java short-circuits `&&` and does NOT evaluate `10 / x`. So `ok` becomes false and prints `false`.
Common Mistake
Watch Out!
Assuming both sides of `&&` always run, leading to a mistaken divide-by-zero.
AP Exam Strategy
With `&&`, if the left side is false, the right side is skipped.
Master This Topic
This Cycle 2 HARD question tests short-circuit evaluation. Review Unit 2 concepts to build mastery of selection and iteration.
- Understanding short-circuit evaluation
- Tracing code execution accurately
- Avoiding common pitfalls
Ready for More Challenges?
Cycle 2 questions prepare you for the hardest AP CSA exam questions.
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