AP CSA Array Max Min Count

Array Max, Min, and Count Patterns in AP CSA

Three of the most tested array algorithms on the AP exam. These patterns appear in FRQs almost every year, often combined with other conditions.

Finding the Maximum

int[] scores = {72, 95, 88, 61, 99, 84};

// Initialize max to FIRST element, not 0
int max = scores[0];

for (int i = 1; i < scores.length; i++) {
    if (scores[i] > max) {
        max = scores[i];
    }
}
System.out.println("Max: " + max);  // 99
⚠ Don’t Initialize to 0: If all values are negative, initializing max = 0 gives the wrong answer. Always initialize to arr[0] or use Integer.MIN_VALUE.

Finding the Minimum

int min = scores[0];
for (int score : scores) {
    if (score < min) {
        min = score;
    }
}
System.out.println("Min: " + min);  // 61

Counting Elements that Meet a Condition

int count = 0;
for (int score : scores) {
    if (score >= 90) {
        count++;
    }
}
System.out.println("Count of 90+: " + count);  // 2

📝 Practice Question 1

Consider an array vals containing only negative integers. Which initialization for finding the maximum value is correct?

📝 Practice Question 2

What does the following method return when called with {3, 7, 2, 7, 5}?

public static int mystery(int[] arr) {
    int count = 0;
    int max = arr[0];
    for (int v : arr) if (v > max) max = v;
    for (int v : arr) if (v == max) count++;
    return count;
}
✅ Exam Tip: FRQ questions often ask for max index (not just max value) or require you to count occurrences of the max. Track the index too: int maxIndex = 0; and update it inside your if statement.

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