The AP exam tests both using Collections.sort() for built-in sorting and implementing selection sort or insertion sort manually — usually on arrays. Know both.
Finds the minimum in the unsorted section and swaps it into position. O(n²) time.
int[] arr = {5, 2, 8, 1, 9};
for (int i = 0; i < arr.length - 1; i++) {
int minIdx = i;
for (int j = i + 1; j < arr.length; j++) {
if (arr[j] < arr[minIdx]) {
minIdx = j;
}
}
// Swap arr[i] and arr[minIdx]
int temp = arr[i];
arr[i] = arr[minIdx];
arr[minIdx] = temp;
}
Insertion Sort: Builds sorted section by picking each element and inserting it into the correct position. Also O(n²) but faster in practice on nearly-sorted data.
📝 Practice Question 1
What is the state of array {4, 2, 7, 1} after ONE complete pass of selection sort (i=0)?
📝 Practice Question 2
Which statement about Collections.sort() is correct?
I. It works on arrays and ArrayLists II. It sorts an ArrayList of Integer in ascending order by default III. It can only sort String ArrayLists
✅ Exam Tip: The AP exam always asks you to trace sorting algorithms step by step. For selection sort, remember: the outer loop index marks where the minimum gets placed. After pass i, positions 0 through i are in their final sorted positions.
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