AP CSA 2.3 Exercise 1: Grade Bands

Unit 2: Selection and Iteration · Lesson 2.3 · Exercise 1

Grade Bands

if Statements. Write real Java, run it, and submit it to be graded against hidden test cases.

Back to the Lesson 2.3 page All Unit 2 lessons

Why this one is worth doing

A chain of else if stops at the first branch that matches. Writing the same chain as four separate ifs changes what it does, and this exercise is graded on the difference.

What to write

Read one integer score between 0 and 100.
Print the letter grade: A for 90 and above, B for 80 to 89, C for 70 to 79, D for 60 to 69, and F below 60.
On the second line print PASS when the score is 60 or more and FAIL otherwise.
On the third line print how far the score is from 100.

Your program reads

A single integer from 0 to 100.

Your program prints

Three lines: the letter grade, PASS or FAIL, and the distance from 100.

Worked examples

These are the cases you can see. There are more you cannot, and they use different values, so an answer that prints these numbers as constants will fail.

Example 1 input

Example 1 output

A
PASS
5

Example 2 input

Example 2 output

C
PASS
28

Your answer

Main.java

import java.util.Scanner;

public class Main {
  public static void main(String[] args) {
    Scanner input = new Scanner(System.in);
    int score = input.nextInt();

    // Use one if / else if chain for the letter, not five separate ifs.
  }
}

Input for the Run button

Run sends whatever is in the input box below. Submitting runs your program against every test case, including hidden ones with different input.

Stuck?

Hint 1

Order the chain from the highest band down. Starting at score >= 60 puts every A in the D branch.

Hint 2

else if means the test is only reached when everything above it was false, so you do not need score >= 80 && score < 90.

Hint 3

Exactly one letter should be printed. If you see two, you wrote separate ifs instead of one chain.

Where to go next

Rework the Lesson 2.3 page Pick another Unit 2 lesson

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