Sample QOTD

Unit 2 - Day 5

Compound Boolean Expressions

AP CSA 2025-26 Medium Difficulty ~3 min
Consider the following code segment.
int x = 7; int y = 3; boolean result = (x > 5) && (y < 5) || (x == y); System.out.println(result);
A)
B)
C)
D)

Why A is correct:

The expression evaluates step by step: (x > 5) is true, (y < 5) is true. true && true gives true. Since the first part of the || is already true, the entire expression is true.

Why the other options are wrong:

A) This is correct - see explanation above.

B) This would only be correct if both conditions in the && were false, or if the && result was false AND (x == y) was also false.

C) The code is syntactically correct. Boolean expressions with && and || are valid in Java.

D) There is no operation here that could cause a runtime error (no division, no array access, no null reference).

AP Exam Tip

Remember operator precedence: && is evaluated before ||. Always trace compound boolean expressions step by step, evaluating each part separately before combining.

← Day 4: Nested If All Questions Day 6: Equivalent Booleans →

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