AP CSA Unit 2 Day 27: Iteration Selection Nested Filtering

Unit 2, Selection & Iteration • Cycle 2
Day 27 Advanced Practice • Harder Difficulty
Focus: Nested Filtering Hard Iteration + Selection (nested filtering)

Advanced Practice Question

Format: Iteration + Selection (nested filtering)

What is printed?
for (int i = 1; i <= 20; i++) {
    if (i % 2 == 0) {
        if (i % 5 == 0) {
            System.out.print(i + " ");
        }
    }
}
Difficulty: Hard | Topic: Iteration + Selection (nested filtering) | Cycle: 2 (Advanced)
Why This Answer?

For each i, odd j values are 1 and 3, so c increments 2 times per outer iteration. Two outer iterations → 4.

Common Mistake
Watch Out!

Counting all j values (4 per i) instead of only odd j values (2 per i).

AP Exam Strategy

When a condition filters iterations, count only the values that pass.

Master This Topic

This Cycle 2 HARD question tests nested filtering. Review Unit 2 concepts to build mastery of selection and iteration.

  • Understanding nested filtering
  • Tracing code execution accurately
  • Avoiding common pitfalls
View Unit 2 Study Guide

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